Base | Representation |
---|---|
bin | 101001110110101110110… |
… | …0011101000010111010011 |
3 | 202100221021202122012222011 |
4 | 1103231131203220113103 |
5 | 1223222140343041203 |
6 | 20122402015523351 |
7 | 1132415035165651 |
oct | 123553543502723 |
9 | 22327252565864 |
10 | 5752530830803 |
11 | 19186a875a909 |
12 | 78aa66b29557 |
13 | 3295cc706533 |
14 | 15c5d1575dd1 |
15 | 9e98343976d |
hex | 53b5d8e85d3 |
5752530830803 has 4 divisors (see below), whose sum is σ = 5752538392888. Its totient is φ = 5752523268720.
The previous prime is 5752530830743. The next prime is 5752530830833. The reversal of 5752530830803 is 3080380352575.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 5752530830803 - 217 = 5752530699731 is a prime.
It is a super-2 number, since 2×57525308308032 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (5752530830833) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2493933 + ... + 4210078.
It is an arithmetic number, because the mean of its divisors is an integer number (1438134598222).
Almost surely, 25752530830803 is an apocalyptic number.
5752530830803 is a deficient number, since it is larger than the sum of its proper divisors (7562085).
5752530830803 is an equidigital number, since it uses as much as digits as its factorization.
5752530830803 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7562084.
The product of its (nonzero) digits is 3024000, while the sum is 49.
The spelling of 5752530830803 in words is "five trillion, seven hundred fifty-two billion, five hundred thirty million, eight hundred thirty thousand, eight hundred three".
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