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57531011251603 = 149938379593897
BaseRepresentation
bin11010001010010111110110…
…11111010011110110010011
321112200220121002110202112211
431011023323133103312103
530020042002340022403
6322205214240532551
715055323043022161
oct1505137337236623
9245626532422484
1057531011251603
111737084602618a
126551a8b321157
1326141c6c0aa96
14102c731508231
1569b7a877106d
hex3452fb7d3d93

57531011251603 has 4 divisors (see below), whose sum is σ = 57569390847000. Its totient is φ = 57492631656208.

The previous prime is 57531011251559. The next prime is 57531011251619. The reversal of 57531011251603 is 30615211013575.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-57531011251603 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (57531011051603) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 19189795450 + ... + 19189798447.

It is an arithmetic number, because the mean of its divisors is an integer number (14392347711750).

Almost surely, 257531011251603 is an apocalyptic number.

57531011251603 is a deficient number, since it is larger than the sum of its proper divisors (38379595397).

57531011251603 is a wasteful number, since it uses less digits than its factorization.

57531011251603 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 38379595396.

The product of its (nonzero) digits is 94500, while the sum is 40.

The spelling of 57531011251603 in words is "fifty-seven trillion, five hundred thirty-one billion, eleven million, two hundred fifty-one thousand, six hundred three".

Divisors: 1 1499 38379593897 57531011251603