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57536113 = 211272683
BaseRepresentation
bin1101101101111…
…0111001110001
311000021010201011
43123132321301
5104212123423
65413110521
71266022525
oct333367161
9130233634
1057536113
112a528808
1217328441
13bbc664b
1478d9d85
1550b7b0d
hex36dee71

57536113 has 4 divisors (see below), whose sum is σ = 57809008. Its totient is φ = 57263220.

The previous prime is 57536081. The next prime is 57536137. The reversal of 57536113 is 31163575.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 57536113 - 25 = 57536081 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (57536173) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 136131 + ... + 136552.

It is an arithmetic number, because the mean of its divisors is an integer number (14452252).

Almost surely, 257536113 is an apocalyptic number.

It is an amenable number.

57536113 is a deficient number, since it is larger than the sum of its proper divisors (272895).

57536113 is a wasteful number, since it uses less digits than its factorization.

57536113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 272894.

The product of its digits is 9450, while the sum is 31.

The square root of 57536113 is about 7585.2562909898. The cubic root of 57536113 is about 386.0529181031.

Adding to 57536113 its reverse (31163575), we get a palindrome (88699688).

The spelling of 57536113 in words is "fifty-seven million, five hundred thirty-six thousand, one hundred thirteen".

Divisors: 1 211 272683 57536113