Base | Representation |
---|---|
bin | 11010001110110110111100… |
… | …01111100111010110111011 |
3 | 21120020122102112210222200112 |
4 | 31013123132033213112323 |
5 | 30030103131142424403 |
6 | 322404104234254535 |
7 | 15102420346603442 |
oct | 1507333617472673 |
9 | 246218375728615 |
10 | 57685139420603 |
11 | 17420148399852 |
12 | 657792458744b |
13 | 26258ba805b96 |
14 | 1035d93253d59 |
15 | 6a07c99919d8 |
hex | 3476de3e75bb |
57685139420603 has 16 divisors (see below), whose sum is σ = 58255461834336. Its totient is φ = 57115401799680.
The previous prime is 57685139420599. The next prime is 57685139420611. The reversal of 57685139420603 is 30602493158675.
It is a cyclic number.
It is not a de Polignac number, because 57685139420603 - 22 = 57685139420599 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (57685139420683) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3256646675 + ... + 3256664387.
It is an arithmetic number, because the mean of its divisors is an integer number (3640966364646).
It is a 1-persistent number, because it is pandigital, but 2⋅57685139420603 = 115370278841206 is not.
Almost surely, 257685139420603 is an apocalyptic number.
57685139420603 is a deficient number, since it is larger than the sum of its proper divisors (570322413733).
57685139420603 is a wasteful number, since it uses less digits than its factorization.
57685139420603 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 32414.
The product of its (nonzero) digits is 32659200, while the sum is 59.
The spelling of 57685139420603 in words is "fifty-seven trillion, six hundred eighty-five billion, one hundred thirty-nine million, four hundred twenty thousand, six hundred three".
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