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5796921433 = 11311512503
BaseRepresentation
bin1010110011000011…
…00000000001011001
3112221222221010020211
411121201200001121
543333002441213
62355120051121
7263440006402
oct53141400131
915858833224
105796921433
112505235966
121159463aa1
13714ca4434
143cdc689a9
1523ddc153d
hex159860059

5796921433 has 4 divisors (see below), whose sum is σ = 5797445248. Its totient is φ = 5796397620.

The previous prime is 5796921421. The next prime is 5796921457. The reversal of 5796921433 is 3341296975.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 5796921433 - 221 = 5794824281 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (5796921233) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 244941 + ... + 267562.

It is an arithmetic number, because the mean of its divisors is an integer number (1449361312).

Almost surely, 25796921433 is an apocalyptic number.

It is an amenable number.

5796921433 is a deficient number, since it is larger than the sum of its proper divisors (523815).

5796921433 is a wasteful number, since it uses less digits than its factorization.

5796921433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 523814.

The product of its digits is 1224720, while the sum is 49.

The square root of 5796921433 is about 76137.5165933326. The cubic root of 5796921433 is about 1796.3838339858.

The spelling of 5796921433 in words is "five billion, seven hundred ninety-six million, nine hundred twenty-one thousand, four hundred thirty-three".

Divisors: 1 11311 512503 5796921433