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58012113 = 319337371
BaseRepresentation
bin1101110101001…
…1000111010001
311001011022122210
43131103013101
5104322341423
65431222333
71303044345
oct335230721
9131138583
1058012113
112a8233a5
12175179a9
13c0321c3
1479c1625
15515db93
hex37531d1

58012113 has 4 divisors (see below), whose sum is σ = 77349488. Its totient is φ = 38674740.

The previous prime is 58012099. The next prime is 58012153. The reversal of 58012113 is 31121085.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 58012113 - 25 = 58012081 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 58012113.

It is not an unprimeable number, because it can be changed into a prime (58012153) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9668683 + ... + 9668688.

It is an arithmetic number, because the mean of its divisors is an integer number (19337372).

Almost surely, 258012113 is an apocalyptic number.

It is an amenable number.

58012113 is a deficient number, since it is larger than the sum of its proper divisors (19337375).

58012113 is a wasteful number, since it uses less digits than its factorization.

58012113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 19337374.

The product of its (nonzero) digits is 240, while the sum is 21.

The square root of 58012113 is about 7616.5683217575. The cubic root of 58012113 is about 387.1146092726.

Adding to 58012113 its reverse (31121085), we get a palindrome (89133198).

The spelling of 58012113 in words is "fifty-eight million, twelve thousand, one hundred thirteen".

Divisors: 1 3 19337371 58012113