Base | Representation |
---|---|
bin | 101010001110101101111… |
… | …0101110111101110011001 |
3 | 202112212020122100202002011 |
4 | 1110131123311313232121 |
5 | 1230043134131243213 |
6 | 20202201231505521 |
7 | 1136220364103254 |
oct | 124353365675631 |
9 | 22485218322064 |
10 | 5804041665433 |
11 | 1938531233320 |
12 | 798a419882a1 |
13 | 33141b48cc3b |
14 | 160cba7ca09b |
15 | a0e9a76903d |
hex | 5475bd77b99 |
5804041665433 has 16 divisors (see below), whose sum is σ = 6404185080000. Its totient is φ = 5216007329280.
The previous prime is 5804041665347. The next prime is 5804041665449. The reversal of 5804041665433 is 3345661404085.
It is not a de Polignac number, because 5804041665433 - 213 = 5804041657241 is a prime.
It is a super-3 number, since 3×58040416654333 (a number of 39 digits) contains 333 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (5804041645433) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3996193 + ... + 5251441.
It is an arithmetic number, because the mean of its divisors is an integer number (400261567500).
Almost surely, 25804041665433 is an apocalyptic number.
It is an amenable number.
5804041665433 is a deficient number, since it is larger than the sum of its proper divisors (600143414567).
5804041665433 is a wasteful number, since it uses less digits than its factorization.
5804041665433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1260072.
The product of its (nonzero) digits is 4147200, while the sum is 49.
The spelling of 5804041665433 in words is "five trillion, eight hundred four billion, forty-one million, six hundred sixty-five thousand, four hundred thirty-three".
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