Base | Representation |
---|---|
bin | 110110011000111110… |
… | …101011110011001011 |
3 | 12120202002001111122202 |
4 | 312120332223303023 |
5 | 1424101143102021 |
6 | 42455031110415 |
7 | 4135143350660 |
oct | 663076536313 |
9 | 176662044582 |
10 | 58401144011 |
11 | 22849a17981 |
12 | b39a51240b |
13 | 5679435062 |
14 | 2b803b9a67 |
15 | 17bc1cca0b |
hex | d98fabccb |
58401144011 has 4 divisors (see below), whose sum is σ = 66744164592. Its totient is φ = 50058123432.
The previous prime is 58401144007. The next prime is 58401144023. The reversal of 58401144011 is 11044110485.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 58401144011 - 22 = 58401144007 is a prime.
It is a super-2 number, since 2×584011440112 (a number of 22 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (58401144031) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4171510280 + ... + 4171510293.
It is an arithmetic number, because the mean of its divisors is an integer number (16686041148).
Almost surely, 258401144011 is an apocalyptic number.
58401144011 is a deficient number, since it is larger than the sum of its proper divisors (8343020581).
58401144011 is an equidigital number, since it uses as much as digits as its factorization.
58401144011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8343020580.
The product of its (nonzero) digits is 2560, while the sum is 29.
Adding to 58401144011 its reverse (11044110485), we get a palindrome (69445254496).
The spelling of 58401144011 in words is "fifty-eight billion, four hundred one million, one hundred forty-four thousand, eleven".
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