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58791941041 = 173458349473
BaseRepresentation
bin110110110000010001…
…011101001110110001
312121202022102001101211
4312300101131032301
51430401214103131
643001511200121
74150630152631
oct666021351661
9177668361354
1058791941041
1122a2a577529
12b489376041
13570c3a37c2
142bba2666c1
1517e16745b1
hexdb045d3b1

58791941041 has 4 divisors (see below), whose sum is σ = 62250290532. Its totient is φ = 55333591552.

The previous prime is 58791941003. The next prime is 58791941111. The reversal of 58791941041 is 14014919785.

58791941041 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 28826946225 + 29964994816 = 169785^2 + 173104^2 .

It is a cyclic number.

It is not a de Polignac number, because 58791941041 - 219 = 58791416753 is a prime.

It is not an unprimeable number, because it can be changed into a prime (58791944041) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1729174720 + ... + 1729174753.

It is an arithmetic number, because the mean of its divisors is an integer number (15562572633).

Almost surely, 258791941041 is an apocalyptic number.

It is an amenable number.

58791941041 is a deficient number, since it is larger than the sum of its proper divisors (3458349491).

58791941041 is a wasteful number, since it uses less digits than its factorization.

58791941041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3458349490.

The product of its (nonzero) digits is 362880, while the sum is 49.

The spelling of 58791941041 in words is "fifty-eight billion, seven hundred ninety-one million, nine hundred forty-one thousand, forty-one".

Divisors: 1 17 3458349473 58791941041