Base | Representation |
---|---|
bin | 1010111110111110… |
… | …11011001000110001 |
3 | 120012222022200200221 |
4 | 11133133123020301 |
5 | 44034120243213 |
6 | 2413054013041 |
7 | 266064005464 |
oct | 53737331061 |
9 | 16188280627 |
10 | 5897040433 |
11 | 25567a8839 |
12 | 1186aa7181 |
13 | 72c95a14b |
14 | 3dd28b2db |
15 | 247a9b38d |
hex | 15f7db231 |
5897040433 has 4 divisors (see below), whose sum is σ = 5901505828. Its totient is φ = 5892575040.
The previous prime is 5897040377. The next prime is 5897040451. The reversal of 5897040433 is 3340407985.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 5410043809 + 486996624 = 73553^2 + 22068^2 .
It is a cyclic number.
It is not a de Polignac number, because 5897040433 - 29 = 5897039921 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 5897040433.
It is not an unprimeable number, because it can be changed into a prime (5897040463) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2230716 + ... + 2233357.
It is an arithmetic number, because the mean of its divisors is an integer number (1475376457).
Almost surely, 25897040433 is an apocalyptic number.
It is an amenable number.
5897040433 is a deficient number, since it is larger than the sum of its proper divisors (4465395).
5897040433 is a wasteful number, since it uses less digits than its factorization.
5897040433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4465394.
The product of its (nonzero) digits is 362880, while the sum is 43.
The square root of 5897040433 is about 76792.1899218924. The cubic root of 5897040433 is about 1806.6666806272. Note that the first 4 decimals are identical.
The spelling of 5897040433 in words is "five billion, eight hundred ninety-seven million, forty thousand, four hundred thirty-three".
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