Base | Representation |
---|---|
bin | 101011001101011000010… |
… | …1101100011110001110001 |
3 | 210000201120220112212021112 |
4 | 1112122300231203301301 |
5 | 1234244233020123423 |
6 | 20344054244203105 |
7 | 1152023165115662 |
oct | 126326055436161 |
9 | 23021526485245 |
10 | 5938609536113 |
11 | 198a60629a291 |
12 | 7bab38399495 |
13 | 341015812817 |
14 | 1676047cb369 |
15 | a4724625a78 |
hex | 566b0b63c71 |
5938609536113 has 4 divisors (see below), whose sum is σ = 5942418780480. Its totient is φ = 5934800291748.
The previous prime is 5938609536109. The next prime is 5938609536127. The reversal of 5938609536113 is 3116359068395.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 5938609536113 - 22 = 5938609536109 is a prime.
It is a super-2 number, since 2×59386095361132 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (5938609536163) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1904619845 + ... + 1904622962.
It is an arithmetic number, because the mean of its divisors is an integer number (1485604695120).
Almost surely, 25938609536113 is an apocalyptic number.
It is an amenable number.
5938609536113 is a deficient number, since it is larger than the sum of its proper divisors (3809244367).
5938609536113 is a wasteful number, since it uses less digits than its factorization.
5938609536113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3809244366.
The product of its (nonzero) digits is 15746400, while the sum is 59.
The spelling of 5938609536113 in words is "five trillion, nine hundred thirty-eight billion, six hundred nine million, five hundred thirty-six thousand, one hundred thirteen".
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