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5945490113 = 8371632411
BaseRepresentation
bin1011000100110000…
…01111101011000001
3120100100111012011112
411202120033223001
544134021140423
62421544253105
7300222555263
oct54230175301
916310435145
105945490113
11258108a7a2
12119b171195
137399c19b4
1440589db33
1524be6ba78
hex16260fac1

5945490113 has 4 divisors (see below), whose sum is σ = 6017122608. Its totient is φ = 5873857620.

The previous prime is 5945490101. The next prime is 5945490149. The reversal of 5945490113 is 3110945495.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 5945490113 - 24 = 5945490097 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (5945490613) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 35816123 + ... + 35816288.

It is an arithmetic number, because the mean of its divisors is an integer number (1504280652).

Almost surely, 25945490113 is an apocalyptic number.

It is an amenable number.

5945490113 is a deficient number, since it is larger than the sum of its proper divisors (71632495).

5945490113 is an equidigital number, since it uses as much as digits as its factorization.

5945490113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 71632494.

The product of its (nonzero) digits is 97200, while the sum is 41.

The square root of 5945490113 is about 77107.0043057049. The cubic root of 5945490113 is about 1811.6010083707.

The spelling of 5945490113 in words is "five billion, nine hundred forty-five million, four hundred ninety thousand, one hundred thirteen".

Divisors: 1 83 71632411 5945490113