Base | Representation |
---|---|
bin | 101011110000001000010… |
… | …0100111001101000100011 |
3 | 210021212012111111012202020 |
4 | 1113200100210321220203 |
5 | 1242010044433314412 |
6 | 20442235113352523 |
7 | 1160304334255512 |
oct | 127402044715043 |
9 | 23255174435666 |
10 | 6013232323107 |
11 | 1a09219977679 |
12 | 8114a3408743 |
13 | 3480788c5299 |
14 | 16b083352679 |
15 | a66409cb18c |
hex | 57810939a23 |
6013232323107 has 4 divisors (see below), whose sum is σ = 8017643097480. Its totient is φ = 4008821548736.
The previous prime is 6013232323067. The next prime is 6013232323127. The reversal of 6013232323107 is 7013232323106.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 6013232323107 - 211 = 6013232321059 is a prime.
It is a super-2 number, since 2×60132323231072 (a number of 26 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (6013232323127) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1002205387182 + ... + 1002205387187.
It is an arithmetic number, because the mean of its divisors is an integer number (2004410774370).
Almost surely, 26013232323107 is an apocalyptic number.
6013232323107 is a deficient number, since it is larger than the sum of its proper divisors (2004410774373).
6013232323107 is a wasteful number, since it uses less digits than its factorization.
6013232323107 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2004410774372.
The product of its (nonzero) digits is 27216, while the sum is 33.
Subtracting 6013232323107 from its reverse (7013232323106), we obtain a palindrome (999999999999).
The spelling of 6013232323107 in words is "six trillion, thirteen billion, two hundred thirty-two million, three hundred twenty-three thousand, one hundred seven".
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