60401423543331 has 8 divisors (see below), whose sum is σ = 86730249190480. Its totient is φ = 37170106795872.

The previous prime is 60401423543327. The next prime is 60401423543411. The reversal of 60401423543331 is 13334532410406.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 60401423543331 - 2² = 60401423543327 is a prime.

It is a super-3 number, since 3×60401423543331³ (a number of 42 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Harshad number since it is a multiple of its sum of digits (39), and also a Moran number because the ratio is a prime number: 1548754449829 = 60401423543331 / (6 + 0 + 4 + 0 + 1 + 4 + 2 + 3 + 5 + 4 + 3 + 3 + 3 + 1).

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 60401423543331.

It is not an unprimeable number, because it can be changed into a prime (60401423543431) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 774377224876 + ... + 774377224953.

It is an arithmetic number, because the mean of its divisors is an integer number (10841281148810).

Almost surely, 2^{60401423543331} is an apocalyptic number.

60401423543331 is a deficient number, since it is larger than the sum of its proper divisors (26328825647149).

60401423543331 is a wasteful number, since it uses less digits than its factorization.

60401423543331 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1548754449845.

The product of its (nonzero) digits is 311040, while the sum is 39.

Adding to 60401423543331 its reverse (13334532410406), we get a palindrome (73735955953737).

The spelling of 60401423543331 in words is "sixty trillion, four hundred one billion, four hundred twenty-three million, five hundred forty-three thousand, three hundred thirty-one".