Base | Representation |
---|---|
bin | 111000010010100000… |
… | …110101001010000011 |
3 | 12210000011210011002101 |
4 | 320102200311022003 |
5 | 1442240133411441 |
6 | 43433225531231 |
7 | 4236522461644 |
oct | 702240651203 |
9 | 183004704071 |
10 | 60440138371 |
11 | 236a5978588 |
12 | b869343b17 |
13 | 59129b32b2 |
14 | 2cd51056cb |
15 | 188b1e4231 |
hex | e12835283 |
60440138371 has 8 divisors (see below), whose sum is σ = 60594649920. Its totient is φ = 60285820608.
The previous prime is 60440138221. The next prime is 60440138399. The reversal of 60440138371 is 17383104406.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 60440138371 - 221 = 60438041219 is a prime.
It is a super-3 number, since 3×604401383713 (a number of 33 digits) contains 333 as substring.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 60440138371.
It is not an unprimeable number, because it can be changed into a prime (60440138771) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 586710 + ... + 681988.
It is an arithmetic number, because the mean of its divisors is an integer number (7574331240).
Almost surely, 260440138371 is an apocalyptic number.
60440138371 is a deficient number, since it is larger than the sum of its proper divisors (154511549).
60440138371 is an equidigital number, since it uses as much as digits as its factorization.
60440138371 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 96893.
The product of its (nonzero) digits is 48384, while the sum is 37.
The spelling of 60440138371 in words is "sixty billion, four hundred forty million, one hundred thirty-eight thousand, three hundred seventy-one".
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