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6074142153 = 32024714051
BaseRepresentation
bin1011010100000110…
…00000110111001001
3120200022120101120220
411222003000313021
544414440022103
62442421540253
7303344233152
oct55203006711
916608511526
106074142153
1126377709a2
121216274689
1375a557a71
144189cc929
152583d0c53
hex16a0c0dc9

6074142153 has 4 divisors (see below), whose sum is σ = 8098856208. Its totient is φ = 4049428100.

The previous prime is 6074142131. The next prime is 6074142163. The reversal of 6074142153 is 3512414706.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 6074142153 - 26 = 6074142089 is a prime.

It is not an unprimeable number, because it can be changed into a prime (6074142163) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1012357023 + ... + 1012357028.

It is an arithmetic number, because the mean of its divisors is an integer number (2024714052).

Almost surely, 26074142153 is an apocalyptic number.

It is an amenable number.

6074142153 is a deficient number, since it is larger than the sum of its proper divisors (2024714055).

6074142153 is a wasteful number, since it uses less digits than its factorization.

6074142153 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2024714054.

The product of its (nonzero) digits is 20160, while the sum is 33.

The square root of 6074142153 is about 77936.7830552429. The cubic root of 6074142153 is about 1824.5747082301.

Adding to 6074142153 its reverse (3512414706), we get a palindrome (9586556859).

The spelling of 6074142153 in words is "six billion, seventy-four million, one hundred forty-two thousand, one hundred fifty-three".

Divisors: 1 3 2024714051 6074142153