6081134113 has 4 divisors (see below), whose sum is σ = 6086148628. Its totient is φ = 6076119600.

The previous prime is 6081134093. The next prime is 6081134173. The reversal of 6081134113 is 3114311806.

6081134113 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 3112300944 + 2968833169 = 55788^2 + 54487^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-6081134113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (6081134173) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2505438 + ... + 2507863.

It is an arithmetic number, because the mean of its divisors is an integer number (1521537157).

Almost surely, 2^6081134113 is an apocalyptic number.

It is an amenable number.

6081134113 is a deficient number, since it is larger than the sum of its proper divisors (5014515).

6081134113 is a wasteful number, since it uses less digits than its factorization.

6081134113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5014514.

The product of its (nonzero) digits is 1728, while the sum is 28.

The square root of 6081134113 is about 77981.6267655401. The cubic root of 6081134113 is about 1825.2745305906.

Adding to 6081134113 its reverse (3114311806), we get a palindrome (9195445919).

The spelling of 6081134113 in words is "six billion, eighty-one million, one hundred thirty-four thousand, one hundred thirteen".