Base | Representation |
---|---|
bin | 101100011001100010000… |
… | …1001100110100101110001 |
3 | 210121100200221021022102020 |
4 | 1120303010021212211301 |
5 | 1244434142432141032 |
6 | 20551141512142053 |
7 | 1166602553455563 |
oct | 130630411464561 |
9 | 23540627238366 |
10 | 6102144412017 |
11 | 1a429a548aa95 |
12 | 826777997929 |
13 | 35357820a194 |
14 | 1714b997b333 |
15 | a8ae65adb2c |
hex | 58cc4266971 |
6102144412017 has 16 divisors (see below), whose sum is σ = 8335115718720. Its totient is φ = 3968646105600.
The previous prime is 6102144411997. The next prime is 6102144412027. The reversal of 6102144412017 is 7102144412016.
It is not a de Polignac number, because 6102144412017 - 210 = 6102144410993 is a prime.
It is a super-3 number, since 3×61021444120173 (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not an unprimeable number, because it can be changed into a prime (6102144412027) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 733209 + ... + 3569577.
It is an arithmetic number, because the mean of its divisors is an integer number (520944732420).
Almost surely, 26102144412017 is an apocalyptic number.
It is an amenable number.
6102144412017 is a deficient number, since it is larger than the sum of its proper divisors (2232971306703).
6102144412017 is a wasteful number, since it uses less digits than its factorization.
6102144412017 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2853904.
The product of its (nonzero) digits is 10752, while the sum is 33.
Subtracting 6102144412017 from its reverse (7102144412016), we obtain a palindrome (999999999999).
The spelling of 6102144412017 in words is "six trillion, one hundred two billion, one hundred forty-four million, four hundred twelve thousand, seventeen".
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