Base | Representation |
---|---|
bin | 111000111010110001… |
… | …010101110101001011 |
3 | 12211202020200212201112 |
4 | 320322301111311023 |
5 | 2000131040231042 |
6 | 44024234240535 |
7 | 4262333435033 |
oct | 707261256513 |
9 | 184666625645 |
10 | 61115555147 |
11 | 23a12157169 |
12 | ba1758614b |
13 | 59bc8c60aa |
14 | 2d5aac08c3 |
15 | 18ca65c982 |
hex | e3ac55d4b |
61115555147 has 4 divisors (see below), whose sum is σ = 61117671216. Its totient is φ = 61113439080.
The previous prime is 61115555141. The next prime is 61115555197. The reversal of 61115555147 is 74155551116.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 61115555147 - 212 = 61115551051 is a prime.
It is a super-2 number, since 2×611155551472 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (61115555141) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1014104 + ... + 1072677.
It is an arithmetic number, because the mean of its divisors is an integer number (15279417804).
Almost surely, 261115555147 is an apocalyptic number.
61115555147 is a deficient number, since it is larger than the sum of its proper divisors (2116069).
61115555147 is a wasteful number, since it uses less digits than its factorization.
61115555147 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2116068.
The product of its digits is 105000, while the sum is 41.
The spelling of 61115555147 in words is "sixty-one billion, one hundred fifteen million, five hundred fifty-five thousand, one hundred forty-seven".
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