Base | Representation |
---|---|
bin | 101100011111001010101… |
… | …0010110100010011101011 |
3 | 210122111221010021102201120 |
4 | 1120332111102310103223 |
5 | 1300133432224401420 |
6 | 21000502231150323 |
7 | 1200511434456612 |
oct | 130762522642353 |
9 | 23574833242646 |
10 | 6114243200235 |
11 | 1a48043985715 |
12 | 828b938153a3 |
13 | 35475597ca71 |
14 | 171d06752879 |
15 | a90a3844d40 |
hex | 58f954b44eb |
6114243200235 has 16 divisors (see below), whose sum is σ = 9785747406336. Its totient is φ = 3259943611488.
The previous prime is 6114243200231. The next prime is 6114243200239. The reversal of 6114243200235 is 5320023424116.
It is an interprime number because it is at equal distance from previous prime (6114243200231) and next prime (6114243200239).
It is not a de Polignac number, because 6114243200235 - 22 = 6114243200231 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 6114243200196 and 6114243200205.
It is not an unprimeable number, because it can be changed into a prime (6114243200231) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 61579699 + ... + 61678908.
It is an arithmetic number, because the mean of its divisors is an integer number (611609212896).
Almost surely, 26114243200235 is an apocalyptic number.
6114243200235 is a deficient number, since it is larger than the sum of its proper divisors (3671504206101).
6114243200235 is a wasteful number, since it uses less digits than its factorization.
6114243200235 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 123261922.
The product of its (nonzero) digits is 34560, while the sum is 33.
The spelling of 6114243200235 in words is "six trillion, one hundred fourteen billion, two hundred forty-three million, two hundred thousand, two hundred thirty-five".
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