Base | Representation |
---|---|
bin | 11011110011100000001011… |
… | …11001100011110111010001 |
3 | 22000111020102110100201102022 |
4 | 31321300011321203313101 |
5 | 31003232340332313131 |
6 | 334012453422301225 |
7 | 15610311550465130 |
oct | 1571600571436721 |
9 | 260436373321368 |
10 | 61143253401041 |
11 | 185337875a8529 |
12 | 6a35b7ba27815 |
13 | 2816a26753c96 |
14 | 11154c64d7917 |
15 | 71072298637b |
hex | 379c05e63dd1 |
61143253401041 has 16 divisors (see below), whose sum is σ = 70789309516800. Its totient is φ = 51726263014608.
The previous prime is 61143253401017. The next prime is 61143253401079. The reversal of 61143253401041 is 14010435234116.
It is not a de Polignac number, because 61143253401041 - 210 = 61143253400017 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 61143253400992 and 61143253401010.
It is not an unprimeable number, because it can be changed into a prime (61143253401011) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 51045821 + ... + 52229898.
It is an arithmetic number, because the mean of its divisors is an integer number (4424331844800).
Almost surely, 261143253401041 is an apocalyptic number.
It is an amenable number.
61143253401041 is a deficient number, since it is larger than the sum of its proper divisors (9646056115759).
61143253401041 is a wasteful number, since it uses less digits than its factorization.
61143253401041 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 103276828.
The product of its (nonzero) digits is 34560, while the sum is 35.
Adding to 61143253401041 its reverse (14010435234116), we get a palindrome (75153688635157).
The spelling of 61143253401041 in words is "sixty-one trillion, one hundred forty-three billion, two hundred fifty-three million, four hundred one thousand, forty-one".
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