61201413000001 has 4 divisors (see below), whose sum is σ = 61270411211712. Its totient is φ = 61132414788292.

The previous prime is 61201412999957. The next prime is 61201413000107. The reversal of 61201413000001 is 10000031410216.

61201413000001 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 61201413000001 - 2²⁹ = 61200876129089 is a prime.

It is a super-2 number, since 2×61201413000001² (a number of 28 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (61201413006001) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 34499104525 + ... + 34499106298.

It is an arithmetic number, because the mean of its divisors is an integer number (15317602802928).

Almost surely, 2^{61201413000001} is an apocalyptic number.

It is an amenable number.

61201413000001 is a deficient number, since it is larger than the sum of its proper divisors (68998211711).

61201413000001 is an equidigital number, since it uses as much as digits as its factorization.

61201413000001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 68998211710.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 61201413000001 its reverse (10000031410216), we get a palindrome (71201444410217).

The spelling of 61201413000001 in words is "sixty-one trillion, two hundred one billion, four hundred thirteen million, one", and thus it is an aban number.