Base | Representation |
---|---|
bin | 11011110111001001111001… |
… | …11100101000100000011011 |
3 | 22000221020022012121102212210 |
4 | 31323210330330220200123 |
5 | 31012311330114124310 |
6 | 334150244431010203 |
7 | 15622343161513215 |
oct | 1573447474504033 |
9 | 260836265542783 |
10 | 61268731004955 |
11 | 18581a1741a531 |
12 | 6a5635a069963 |
13 | 28258027100a6 |
14 | 111b5cb1075b5 |
15 | 713b18785820 |
hex | 37b93cf2881b |
61268731004955 has 16 divisors (see below), whose sum is σ = 98091896348160. Its totient is φ = 32656014289248.
The previous prime is 61268731004953. The next prime is 61268731005019. The reversal of 61268731004955 is 55940013786216.
It is not a de Polignac number, because 61268731004955 - 21 = 61268731004953 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 61268731004895 and 61268731004904.
It is not an unprimeable number, because it can be changed into a prime (61268731004953) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1290115885 + ... + 1290163374.
It is an arithmetic number, because the mean of its divisors is an integer number (6130743521760).
It is a 1-persistent number, because it is pandigital, but 2⋅61268731004955 = 122537462009910 is not.
Almost surely, 261268731004955 is an apocalyptic number.
61268731004955 is a deficient number, since it is larger than the sum of its proper divisors (36823165343205).
61268731004955 is a wasteful number, since it uses less digits than its factorization.
61268731004955 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2580280850.
The product of its (nonzero) digits is 10886400, while the sum is 57.
The spelling of 61268731004955 in words is "sixty-one trillion, two hundred sixty-eight billion, seven hundred thirty-one million, four thousand, nine hundred fifty-five".
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