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61268731004955 = 3515832580279259
BaseRepresentation
bin11011110111001001111001…
…11100101000100000011011
322000221020022012121102212210
431323210330330220200123
531012311330114124310
6334150244431010203
715622343161513215
oct1573447474504033
9260836265542783
1061268731004955
1118581a1741a531
126a5635a069963
1328258027100a6
14111b5cb1075b5
15713b18785820
hex37b93cf2881b

61268731004955 has 16 divisors (see below), whose sum is σ = 98091896348160. Its totient is φ = 32656014289248.

The previous prime is 61268731004953. The next prime is 61268731005019. The reversal of 61268731004955 is 55940013786216.

It is not a de Polignac number, because 61268731004955 - 21 = 61268731004953 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 61268731004895 and 61268731004904.

It is not an unprimeable number, because it can be changed into a prime (61268731004953) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1290115885 + ... + 1290163374.

It is an arithmetic number, because the mean of its divisors is an integer number (6130743521760).

It is a 1-persistent number, because it is pandigital, but 2⋅61268731004955 = 122537462009910 is not.

Almost surely, 261268731004955 is an apocalyptic number.

61268731004955 is a deficient number, since it is larger than the sum of its proper divisors (36823165343205).

61268731004955 is a wasteful number, since it uses less digits than its factorization.

61268731004955 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2580280850.

The product of its (nonzero) digits is 10886400, while the sum is 57.

The spelling of 61268731004955 in words is "sixty-one trillion, two hundred sixty-eight billion, seven hundred thirty-one million, four thousand, nine hundred fifty-five".

Divisors: 1 3 5 15 1583 4749 7915 23745 2580279259 7740837777 12901396295 38704188885 4084582066997 12253746200991 20422910334985 61268731004955