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61271239873 = 232663966951
BaseRepresentation
bin111001000100000011…
…001110110011000001
312212011002122111000111
4321010003032303001
52000440414133443
644051515151321
74266233642254
oct710403166301
9185132574014
1061271239873
1123a92021428
12ba5b745541
135a15c3562c
142d7364909b
1518d916169d
hexe440cecc1

61271239873 has 4 divisors (see below), whose sum is σ = 63935206848. Its totient is φ = 58607272900.

The previous prime is 61271239867. The next prime is 61271239937. The reversal of 61271239873 is 37893217216.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a de Polignac number, because none of the positive numbers 2k-61271239873 is a prime.

It is a super-2 number, since 2×612712398732 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (61271239823) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1331983453 + ... + 1331983498.

It is an arithmetic number, because the mean of its divisors is an integer number (15983801712).

Almost surely, 261271239873 is an apocalyptic number.

It is an amenable number.

61271239873 is a deficient number, since it is larger than the sum of its proper divisors (2663966975).

61271239873 is a wasteful number, since it uses less digits than its factorization.

61271239873 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2663966974.

The product of its digits is 762048, while the sum is 49.

The spelling of 61271239873 in words is "sixty-one billion, two hundred seventy-one million, two hundred thirty-nine thousand, eight hundred seventy-three".

Divisors: 1 23 2663966951 61271239873