Base | Representation |
---|---|
bin | 111001001000010011… |
… | …001111000111100001 |
3 | 12212100001211010101011 |
4 | 321020103033013201 |
5 | 2001112142404403 |
6 | 44102543340521 |
7 | 4301061011116 |
oct | 711023170741 |
9 | 185301733334 |
10 | 61342544353 |
11 | 240192a3552 |
12 | ba7b5b1741 |
13 | 5a2793cb2c |
14 | 2d7ccca90d |
15 | 18e0548a6d |
hex | e484cf1e1 |
61342544353 has 4 divisors (see below), whose sum is σ = 61421901588. Its totient is φ = 61263187120.
The previous prime is 61342544327. The next prime is 61342544369. The reversal of 61342544353 is 35344524316.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 9744058944 + 51598485409 = 98712^2 + 227153^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-61342544353 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (61342544453) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 39677458 + ... + 39679003.
It is an arithmetic number, because the mean of its divisors is an integer number (15355475397).
Almost surely, 261342544353 is an apocalyptic number.
It is an amenable number.
61342544353 is a deficient number, since it is larger than the sum of its proper divisors (79357235).
61342544353 is an equidigital number, since it uses as much as digits as its factorization.
61342544353 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 79357234.
The product of its digits is 518400, while the sum is 40.
The spelling of 61342544353 in words is "sixty-one billion, three hundred forty-two million, five hundred forty-four thousand, three hundred fifty-three".
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