Search a number
-
+
61413012483 = 320471004161
BaseRepresentation
bin111001001100100000…
…000011010000000011
312212111222102021110220
4321030200003100003
52001233212344413
644113541554123
74302604664424
oct711440032003
9185458367426
1061413012483
1124055054279
12ba9b115943
135a39413754
142d883d164b
1518e6818223
hexe4c803403

61413012483 has 4 divisors (see below), whose sum is σ = 81884016648. Its totient is φ = 40942008320.

The previous prime is 61413012469. The next prime is 61413012491. The reversal of 61413012483 is 38421031416.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 61413012483 - 213 = 61413004291 is a prime.

It is a super-2 number, since 2×614130124832 (a number of 22 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (61413012443) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10235502078 + ... + 10235502083.

It is an arithmetic number, because the mean of its divisors is an integer number (20471004162).

Almost surely, 261413012483 is an apocalyptic number.

61413012483 is a deficient number, since it is larger than the sum of its proper divisors (20471004165).

61413012483 is a wasteful number, since it uses less digits than its factorization.

61413012483 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 20471004164.

The product of its (nonzero) digits is 13824, while the sum is 33.

Adding to 61413012483 its reverse (38421031416), we get a palindrome (99834043899).

The spelling of 61413012483 in words is "sixty-one billion, four hundred thirteen million, twelve thousand, four hundred eighty-three".

Divisors: 1 3 20471004161 61413012483