Base | Representation |
---|---|
bin | 111001001101101101… |
… | …000100010101100011 |
3 | 12212120101102000022111 |
4 | 321031231010111203 |
5 | 2001303344431034 |
6 | 44115542420151 |
7 | 4303241413150 |
oct | 711555042543 |
9 | 185511360274 |
10 | 61433202019 |
11 | 24065493a42 |
12 | baa5a31657 |
13 | 5a40662217 |
14 | 2d8ad69227 |
15 | 18e84a5364 |
hex | e4db44563 |
61433202019 has 4 divisors (see below), whose sum is σ = 70209373744. Its totient is φ = 52657030296.
The previous prime is 61433202011. The next prime is 61433202029. The reversal of 61433202019 is 91020233416.
61433202019 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 61433202019 - 23 = 61433202011 is a prime.
It is a super-2 number, since 2×614332020192 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (61433202011) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4388085852 + ... + 4388085865.
It is an arithmetic number, because the mean of its divisors is an integer number (17552343436).
Almost surely, 261433202019 is an apocalyptic number.
61433202019 is a deficient number, since it is larger than the sum of its proper divisors (8776171725).
61433202019 is an equidigital number, since it uses as much as digits as its factorization.
61433202019 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8776171724.
The product of its (nonzero) digits is 7776, while the sum is 31.
The spelling of 61433202019 in words is "sixty-one billion, four hundred thirty-three million, two hundred two thousand, nineteen".
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