630354413353 has 4 divisors (see below), whose sum is σ = 720405043840. Its totient is φ = 540303782868.

The previous prime is 630354413321. The next prime is 630354413357. The reversal of 630354413353 is 353314453036.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 630354413353 - 2⁵ = 630354413321 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (630354413357) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 45025315233 + ... + 45025315246.

It is an arithmetic number, because the mean of its divisors is an integer number (180101260960).

Almost surely, 2^630354413353 is an apocalyptic number.

It is an amenable number.

630354413353 is a deficient number, since it is larger than the sum of its proper divisors (90050630487).

630354413353 is an equidigital number, since it uses as much as digits as its factorization.

630354413353 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 90050630486.

The product of its (nonzero) digits is 583200, while the sum is 40.

Adding to 630354413353 its reverse (353314453036), we get a palindrome (983668866389).

The spelling of 630354413353 in words is "six hundred thirty billion, three hundred fifty-four million, four hundred thirteen thousand, three hundred fifty-three".