Base | Representation |
---|---|
bin | 10010011000101010000… |
… | …10110001101010010011 |
3 | 2020101120011220122201101 |
4 | 21030111002301222103 |
5 | 40322222042213442 |
6 | 1202112143045231 |
7 | 63432304646530 |
oct | 11142502615223 |
9 | 2211504818641 |
10 | 631713241747 |
11 | 2239a97244a5 |
12 | a251b5a0817 |
13 | 47754c57103 |
14 | 2280a05dd87 |
15 | 116740b3cb7 |
hex | 93150b1a93 |
631713241747 has 4 divisors (see below), whose sum is σ = 721957990576. Its totient is φ = 541468492920.
The previous prime is 631713241741. The next prime is 631713241781. The reversal of 631713241747 is 747142317136.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 631713241747 - 215 = 631713208979 is a prime.
It is a super-2 number, since 2×6317132417472 (a number of 24 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 631713241697 and 631713241706.
It is not an unprimeable number, because it can be changed into a prime (631713241741) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 45122374404 + ... + 45122374417.
It is an arithmetic number, because the mean of its divisors is an integer number (180489497644).
Almost surely, 2631713241747 is an apocalyptic number.
631713241747 is a deficient number, since it is larger than the sum of its proper divisors (90244748829).
631713241747 is an equidigital number, since it uses as much as digits as its factorization.
631713241747 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 90244748828.
The product of its digits is 592704, while the sum is 46.
The spelling of 631713241747 in words is "six hundred thirty-one billion, seven hundred thirteen million, two hundred forty-one thousand, seven hundred forty-seven".
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