Base | Representation |
---|---|
bin | 11100110110110000101110… |
… | …00110001111001001111011 |
3 | 22022200011110200201012021220 |
4 | 32123120113012033021323 |
5 | 31304113232442421021 |
6 | 342542250044203123 |
7 | 16236263036411652 |
oct | 1633302706171173 |
9 | 268604420635256 |
10 | 63454234342011 |
11 | 19244876046037 |
12 | 7149a328394a3 |
13 | 2953929aca556 |
14 | 11952b6638199 |
15 | 7508cc199cc6 |
hex | 39b61718f27b |
63454234342011 has 4 divisors (see below), whose sum is σ = 84605645789352. Its totient is φ = 42302822894672.
The previous prime is 63454234341997. The next prime is 63454234342019. The reversal of 63454234342011 is 11024343245436.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 63454234342011 - 214 = 63454234325627 is a prime.
It is a super-2 number, since 2×634542343420112 (a number of 28 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (63454234342019) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10575705723666 + ... + 10575705723671.
It is an arithmetic number, because the mean of its divisors is an integer number (21151411447338).
Almost surely, 263454234342011 is an apocalyptic number.
63454234342011 is a deficient number, since it is larger than the sum of its proper divisors (21151411447341).
63454234342011 is a wasteful number, since it uses less digits than its factorization.
63454234342011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 21151411447340.
The product of its (nonzero) digits is 829440, while the sum is 42.
Adding to 63454234342011 its reverse (11024343245436), we get a palindrome (74478577587447).
The spelling of 63454234342011 in words is "sixty-three trillion, four hundred fifty-four billion, two hundred thirty-four million, three hundred forty-two thousand, eleven".
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