6411553031241 has 16 divisors (see below), whose sum is σ = 9998523246400. Its totient is φ = 4049401914144.

The previous prime is 6411553031239. The next prime is 6411553031243. The reversal of 6411553031241 is 1421303551146.

6411553031241 is a `hidden beast` number, since 6 + 4 + 115 + 530 + 3 + 1 + 2 + 4 + 1 = 666.

It is an interprime number because it is at equal distance from previous prime (6411553031239) and next prime (6411553031243).

It is not a de Polignac number, because 6411553031241 - 2¹ = 6411553031239 is a prime.

It is a super-2 number, since 2×6411553031241² (a number of 26 digits) contains 22 as substring.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 6411553031196 and 6411553031205.

It is not an unprimeable number, because it can be changed into a prime (6411553031243) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 6249076516 + ... + 6249077541.

It is an arithmetic number, because the mean of its divisors is an integer number (624907702900).

Almost surely, 2^{6411553031241} is an apocalyptic number.

It is an amenable number.

6411553031241 is a deficient number, since it is larger than the sum of its proper divisors (3586970215159).

6411553031241 is a wasteful number, since it uses less digits than its factorization.

6411553031241 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12498154085 (or 12498154079 counting only the distinct ones).

The product of its (nonzero) digits is 43200, while the sum is 36.

Adding to 6411553031241 its reverse (1421303551146), we get a palindrome (7832856582387).

The spelling of 6411553031241 in words is "six trillion, four hundred eleven billion, five hundred fifty-three million, thirty-one thousand, two hundred forty-one".