Base | Representation |
---|---|
bin | 101110101001101110101… |
… | …1111100111011011001001 |
3 | 211200221222212112210100111 |
4 | 1131103131133213123021 |
5 | 1320022340124231223 |
6 | 21345313225434321 |
7 | 1231144363311622 |
oct | 135233537473311 |
9 | 24627885483314 |
10 | 6411807258313 |
11 | 2052261050776 |
12 | 87679933b9a1 |
13 | 376827c1a302 |
14 | 18249415aa49 |
15 | b1bbc22d30d |
hex | 5d4dd7e76c9 |
6411807258313 has 8 divisors (see below), whose sum is σ = 6451649269632. Its totient is φ = 6371982484896.
The previous prime is 6411807258301. The next prime is 6411807258361. The reversal of 6411807258313 is 3138527081146.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-6411807258313 is a prime.
It is a super-2 number, since 2×64118072583132 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (6411807255313) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3562845 + ... + 5051482.
It is an arithmetic number, because the mean of its divisors is an integer number (806456158704).
Almost surely, 26411807258313 is an apocalyptic number.
It is an amenable number.
6411807258313 is a deficient number, since it is larger than the sum of its proper divisors (39842011319).
6411807258313 is a wasteful number, since it uses less digits than its factorization.
6411807258313 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8618951.
The product of its (nonzero) digits is 967680, while the sum is 49.
The spelling of 6411807258313 in words is "six trillion, four hundred eleven billion, eight hundred seven million, two hundred fifty-eight thousand, three hundred thirteen".
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