Base | Representation |
---|---|
bin | 101110101001111110111… |
… | …1000000010101000110001 |
3 | 211201000101201210221221112 |
4 | 1131103331320002220301 |
5 | 1320024443214012040 |
6 | 21345443154003105 |
7 | 1231164011130425 |
oct | 135237570025061 |
9 | 24630351727845 |
10 | 6412350532145 |
11 | 205250a784408 |
12 | 87690b276495 |
13 | 3768b364410c |
14 | 182506378b85 |
15 | b1beec93365 |
hex | 5d4fde02a31 |
6412350532145 has 8 divisors (see below), whose sum is σ = 7694837730240. Its totient is φ = 5129869031280.
The previous prime is 6412350532109. The next prime is 6412350532153. The reversal of 6412350532145 is 5412350532146.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 6412350532145 - 210 = 6412350531121 is a prime.
It is a super-2 number, since 2×64123505321452 (a number of 26 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1658396 + ... + 3946514.
It is an arithmetic number, because the mean of its divisors is an integer number (961854716280).
Almost surely, 26412350532145 is an apocalyptic number.
It is an amenable number.
6412350532145 is a deficient number, since it is larger than the sum of its proper divisors (1282487198095).
6412350532145 is a wasteful number, since it uses less digits than its factorization.
6412350532145 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2848615.
The product of its (nonzero) digits is 432000, while the sum is 41.
Subtracting from 6412350532145 its reverse (5412350532146), we obtain a palindrome (999999999999).
The spelling of 6412350532145 in words is "six trillion, four hundred twelve billion, three hundred fifty million, five hundred thirty-two thousand, one hundred forty-five".
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