Base | Representation |
---|---|
bin | 101110101010000111101… |
… | …0001101010100111000011 |
3 | 211201001011002010112121211 |
4 | 1131110033101222213003 |
5 | 1320031042432242042 |
6 | 21345532143030551 |
7 | 1231204154366335 |
oct | 135241721524703 |
9 | 24631132115554 |
10 | 6412642462147 |
11 | 205264a546779 |
12 | 876990b9b457 |
13 | 37692bc7796c |
14 | 18253304b455 |
15 | b1c1a70b017 |
hex | 5d50f46a9c3 |
6412642462147 has 16 divisors (see below), whose sum is σ = 6639880690080. Its totient is φ = 6185813356800.
The previous prime is 6412642462139. The next prime is 6412642462201. The reversal of 6412642462147 is 7412642462146.
It is a cyclic number.
It is not a de Polignac number, because 6412642462147 - 23 = 6412642462139 is a prime.
It is a super-2 number, since 2×64126424621472 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 6412642462147.
It is not an unprimeable number, because it can be changed into a prime (6412642462747) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 348257913 + ... + 348276325.
It is an arithmetic number, because the mean of its divisors is an integer number (414992543130).
Almost surely, 26412642462147 is an apocalyptic number.
6412642462147 is a deficient number, since it is larger than the sum of its proper divisors (227238227933).
6412642462147 is a wasteful number, since it uses less digits than its factorization.
6412642462147 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 28854.
The product of its digits is 3096576, while the sum is 49.
Subtracting 6412642462147 from its reverse (7412642462146), we obtain a palindrome (999999999999).
The spelling of 6412642462147 in words is "six trillion, four hundred twelve billion, six hundred forty-two million, four hundred sixty-two thousand, one hundred forty-seven".
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