Base | Representation |
---|---|
bin | 111011101110011101… |
… | …011111011101000011 |
3 | 20010112100101021101022 |
4 | 323232131133131003 |
5 | 2022314321004223 |
6 | 45243325500055 |
7 | 4430131064351 |
oct | 735635373503 |
9 | 203470337338 |
10 | 64130250563 |
11 | 25219944485 |
12 | 1051911162b |
13 | 6080354432 |
14 | 31652307d1 |
15 | 1a05155ac8 |
hex | eee75f743 |
64130250563 has 8 divisors (see below), whose sum is σ = 65519306496. Its totient is φ = 62752089600.
The previous prime is 64130250553. The next prime is 64130250601. The reversal of 64130250563 is 36505203146.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 64130250563 - 232 = 59835283267 is a prime.
It is a super-3 number, since 3×641302505633 (a number of 33 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not an unprimeable number, because it can be changed into a prime (64130250553) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2711843 + ... + 2735388.
It is an arithmetic number, because the mean of its divisors is an integer number (8189913312).
Almost surely, 264130250563 is an apocalyptic number.
64130250563 is a deficient number, since it is larger than the sum of its proper divisors (1389055933).
64130250563 is a wasteful number, since it uses less digits than its factorization.
64130250563 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5447485.
The product of its (nonzero) digits is 64800, while the sum is 35.
The spelling of 64130250563 in words is "sixty-four billion, one hundred thirty million, two hundred fifty thousand, five hundred sixty-three".
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