Base | Representation |
---|---|
bin | 101110101010011011100… |
… | …0000011111101111110001 |
3 | 211201002212112102201000221 |
4 | 1131110313000133233301 |
5 | 1320033424104043331 |
6 | 21350122234213041 |
7 | 1231226530320601 |
oct | 135246700375761 |
9 | 24632775381027 |
10 | 6413309049841 |
11 | 20529618449a1 |
12 | 876b38284181 |
13 | 376a070b8b55 |
14 | 1825977a8c01 |
15 | b1c58ecd711 |
hex | 5d53701fbf1 |
6413309049841 has 8 divisors (see below), whose sum is σ = 6422422089600. Its totient is φ = 6404196548400.
The previous prime is 6413309049751. The next prime is 6413309049853. The reversal of 6413309049841 is 1489409033146.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 6413309049841 - 27 = 6413309049713 is a prime.
It is a super-2 number, since 2×64133090498412 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (6413339049841) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 27819075 + ... + 28048663.
It is an arithmetic number, because the mean of its divisors is an integer number (802802761200).
Almost surely, 26413309049841 is an apocalyptic number.
It is an amenable number.
6413309049841 is a deficient number, since it is larger than the sum of its proper divisors (9113039759).
6413309049841 is a wasteful number, since it uses less digits than its factorization.
6413309049841 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 269159.
The product of its (nonzero) digits is 2239488, while the sum is 52.
The spelling of 6413309049841 in words is "six trillion, four hundred thirteen billion, three hundred nine million, forty-nine thousand, eight hundred forty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •