Base | Representation |
---|---|
bin | 11101001111101110110101… |
… | …00111110110000101010011 |
3 | 22102201012001201022011002222 |
4 | 32213313122213312011103 |
5 | 31412142403034414420 |
6 | 344440342312531255 |
7 | 16355255411366666 |
oct | 1647673247660523 |
9 | 272635051264088 |
10 | 64312213201235 |
11 | 1954572481090a |
12 | 726817a0b0b2b |
13 | 29b68008672cc |
14 | 11c4a28c536dd |
15 | 767d95553225 |
hex | 3a7dda9f6153 |
64312213201235 has 8 divisors (see below), whose sum is σ = 78969415279920. Its totient is φ = 50253264268704.
The previous prime is 64312213201219. The next prime is 64312213201253. The reversal of 64312213201235 is 53210231221346.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 64312213201235 - 24 = 64312213201219 is a prime.
It is a super-2 number, since 2×643122132012352 (a number of 28 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 64312213201195 and 64312213201204.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 149563286300 + ... + 149563286729.
It is an arithmetic number, because the mean of its divisors is an integer number (9871176909990).
Almost surely, 264312213201235 is an apocalyptic number.
64312213201235 is a deficient number, since it is larger than the sum of its proper divisors (14657202078685).
64312213201235 is a wasteful number, since it uses less digits than its factorization.
64312213201235 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 299126573077.
The product of its (nonzero) digits is 51840, while the sum is 35.
The spelling of 64312213201235 in words is "sixty-four trillion, three hundred twelve billion, two hundred thirteen million, two hundred one thousand, two hundred thirty-five".
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