Base | Representation |
---|---|
bin | 11101010100011011100110… |
… | …01010110010111010000011 |
3 | 22110021121212001101222001221 |
4 | 32222031303022302322003 |
5 | 31422314102142240201 |
6 | 345042445205335511 |
7 | 16403033023115533 |
oct | 1652156312627203 |
9 | 273247761358057 |
10 | 64473686290051 |
11 | 195a81560a3445 |
12 | 7293523107597 |
13 | 29c8ac50630cc |
14 | 11cc7862634c3 |
15 | 76c1964c14a1 |
hex | 3aa3732b2e83 |
64473686290051 has 8 divisors (see below), whose sum is σ = 66409982127104. Its totient is φ = 62557249897800.
The previous prime is 64473686290033. The next prime is 64473686290127. The reversal of 64473686290051 is 15009268637446.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 64473686290051 - 231 = 64471538806403 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (64473686290001) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4964854611 + ... + 4964867596.
It is an arithmetic number, because the mean of its divisors is an integer number (8301247765888).
It is a 1-persistent number, because it is pandigital, but 2⋅64473686290051 = 128947372580102 is not.
Almost surely, 264473686290051 is an apocalyptic number.
64473686290051 is a deficient number, since it is larger than the sum of its proper divisors (1936295837053).
64473686290051 is a wasteful number, since it uses less digits than its factorization.
64473686290051 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9929722401.
The product of its (nonzero) digits is 52254720, while the sum is 61.
The spelling of 64473686290051 in words is "sixty-four trillion, four hundred seventy-three billion, six hundred eighty-six million, two hundred ninety thousand, fifty-one".
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