Base | Representation |
---|---|
bin | 10010110001111110001… |
… | …00100011000111101001 |
3 | 2021200122021220200022110 |
4 | 21120333010203013221 |
5 | 41033040113021213 |
6 | 1212240452112533 |
7 | 64423134064161 |
oct | 11307704430751 |
9 | 2250567820273 |
10 | 645303251433 |
11 | 229742953965 |
12 | a5092905749 |
13 | 48b0c637369 |
14 | 23338cd15a1 |
15 | 11bbc20d5c3 |
hex | 963f1231e9 |
645303251433 has 16 divisors (see below), whose sum is σ = 868830110720. Its totient is φ = 425989975824.
The previous prime is 645303251393. The next prime is 645303251477. The reversal of 645303251433 is 334152303546.
645303251433 is digitally balanced in base 2 and base 4, because in such bases it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 645303251433 - 213 = 645303243241 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 645303251391 and 645303251400.
It is not an unprimeable number, because it can be changed into a prime (645303251633) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3930060 + ... + 4090962.
It is an arithmetic number, because the mean of its divisors is an integer number (54301881920).
Almost surely, 2645303251433 is an apocalyptic number.
It is an amenable number.
645303251433 is a deficient number, since it is larger than the sum of its proper divisors (223526859287).
645303251433 is a wasteful number, since it uses less digits than its factorization.
645303251433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 173988.
The product of its (nonzero) digits is 388800, while the sum is 39.
Adding to 645303251433 its reverse (334152303546), we get a palindrome (979455554979).
The spelling of 645303251433 in words is "six hundred forty-five billion, three hundred three million, two hundred fifty-one thousand, four hundred thirty-three".
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