Search a number
-
+
64553251412011 = 79817129764709
BaseRepresentation
bin11101010110101111110011…
…00111101001100000101011
322110120020020002012221112211
432223113321213221200223
531430120024330141021
6345143204310145551
716411550514362245
oct1653277147514053
9273506202187484
1064553251412011
111962897558218a
1272a6a293522b7
132a0346506422b
1411d2573359095
1576e2a16dc3e1
hex3ab5f99e982b

64553251412011 has 4 divisors (see below), whose sum is σ = 65370381176800. Its totient is φ = 63736121647224.

The previous prime is 64553251411993. The next prime is 64553251412059. The reversal of 64553251412011 is 11021415235546.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 64553251412011 - 213 = 64553251403819 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (64553251412081) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 408564882276 + ... + 408564882433.

It is an arithmetic number, because the mean of its divisors is an integer number (16342595294200).

Almost surely, 264553251412011 is an apocalyptic number.

64553251412011 is a deficient number, since it is larger than the sum of its proper divisors (817129764789).

64553251412011 is an equidigital number, since it uses as much as digits as its factorization.

64553251412011 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 817129764788.

The product of its (nonzero) digits is 144000, while the sum is 40.

Adding to 64553251412011 its reverse (11021415235546), we get a palindrome (75574666647557).

The spelling of 64553251412011 in words is "sixty-four trillion, five hundred fifty-three billion, two hundred fifty-one million, four hundred twelve thousand, eleven".

Divisors: 1 79 817129764709 64553251412011