649713403 has 4 divisors (see below), whose sum is σ = 658864368. Its totient is φ = 640562440.

The previous prime is 649713401. The next prime is 649713413. The reversal of 649713403 is 304317946.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 649713403 - 2¹ = 649713401 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (649713401) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4575376 + ... + 4575517.

It is an arithmetic number, because the mean of its divisors is an integer number (164716092).

Almost surely, 2^649713403 is an apocalyptic number.

649713403 is a deficient number, since it is larger than the sum of its proper divisors (9150965).

649713403 is an equidigital number, since it uses as much as digits as its factorization.

649713403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9150964.

The product of its (nonzero) digits is 54432, while the sum is 37.

The square root of 649713403 is about 25489.4763186692. The cubic root of 649713403 is about 866.1117730201. Note that the first 3 decimals are identical.

It can be divided in two parts, 6497 and 13403, that added together give a triangular number (19900 = T₁₉₉).

The spelling of 649713403 in words is "six hundred forty-nine million, seven hundred thirteen thousand, four hundred three".