Base | Representation |
---|---|
bin | 11101100101010011110110… |
… | …01000101001111101010001 |
3 | 22112100001211001121222210010 |
4 | 32302221323020221331101 |
5 | 32011314323434004133 |
6 | 350205121353425133 |
7 | 16462653566616624 |
oct | 1662517310517521 |
9 | 275301731558703 |
10 | 65053640531793 |
11 | 19801104154081 |
12 | 73679b870b1a9 |
13 | 2a3b6bb9b41a4 |
14 | 120c88210ddbb |
15 | 77c2db585263 |
hex | 3b2a7b229f51 |
65053640531793 has 16 divisors (see below), whose sum is σ = 87460695383040. Its totient is φ = 43008543200976.
The previous prime is 65053640531791. The next prime is 65053640531807. The reversal of 65053640531793 is 39713504635056.
It is not a de Polignac number, because 65053640531793 - 21 = 65053640531791 is a prime.
It is a super-2 number, since 2×650536405317932 (a number of 28 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (65053640531791) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 87569205 + ... + 88308962.
It is an arithmetic number, because the mean of its divisors is an integer number (5466293461440).
Almost surely, 265053640531793 is an apocalyptic number.
It is an amenable number.
65053640531793 is a deficient number, since it is larger than the sum of its proper divisors (22407054851247).
65053640531793 is a wasteful number, since it uses less digits than its factorization.
65053640531793 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 175879196.
The product of its (nonzero) digits is 30618000, while the sum is 57.
The spelling of 65053640531793 in words is "sixty-five trillion, fifty-three billion, six hundred forty million, five hundred thirty-one thousand, seven hundred ninety-three".
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