Base | Representation |
---|---|
bin | 111100101001001100… |
… | …011111000000000001 |
3 | 20020002000120122112201 |
4 | 330221030133000001 |
5 | 2031324101214001 |
6 | 45525210153201 |
7 | 4463424606235 |
oct | 745114370001 |
9 | 206060518481 |
10 | 65115648001 |
11 | 256850a4128 |
12 | 10753122801 |
13 | 61a954ab41 |
14 | 321a05a5c5 |
15 | 1a61900501 |
hex | f2931f001 |
65115648001 has 4 divisors (see below), whose sum is σ = 65117173504. Its totient is φ = 65114122500.
The previous prime is 65115647983. The next prime is 65115648041. The reversal of 65115648001 is 10084651156.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 65115648001 - 27 = 65115647873 is a prime.
It is a super-2 number, since 2×651156480012 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (65115648041) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 696825 + ... + 784726.
It is an arithmetic number, because the mean of its divisors is an integer number (16279293376).
Almost surely, 265115648001 is an apocalyptic number.
It is an amenable number.
65115648001 is a deficient number, since it is larger than the sum of its proper divisors (1525503).
65115648001 is a wasteful number, since it uses less digits than its factorization.
65115648001 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1525502.
The product of its (nonzero) digits is 28800, while the sum is 37.
The spelling of 65115648001 in words is "sixty-five billion, one hundred fifteen million, six hundred forty-eight thousand, one".
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