Base | Representation |
---|---|
bin | 11101100111001010001001… |
… | …11111100110111101000011 |
3 | 22112120010202121111122111101 |
4 | 32303211010333212331003 |
5 | 32013334414103344341 |
6 | 350254224145355231 |
7 | 16500362563263535 |
oct | 1663450477467503 |
9 | 275503677448441 |
10 | 65117156699971 |
11 | 198260383a1352 |
12 | 7378184038b17 |
13 | 2a446a1a4bc5c |
14 | 121198996d855 |
15 | 77dca783a831 |
hex | 3b3944fe6f43 |
65117156699971 has 4 divisors (see below), whose sum is σ = 65267542743592. Its totient is φ = 64966770656352.
The previous prime is 65117156699911. The next prime is 65117156699981. The reversal of 65117156699971 is 17999665171156.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 65117156699971 - 213 = 65117156691779 is a prime.
It is a super-2 number, since 2×651171566999712 (a number of 28 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 65117156699894 and 65117156699903.
It is not an unprimeable number, because it can be changed into a prime (65117156699911) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 75193021161 + ... + 75193022026.
It is an arithmetic number, because the mean of its divisors is an integer number (16316885685898).
Almost surely, 265117156699971 is an apocalyptic number.
65117156699971 is a deficient number, since it is larger than the sum of its proper divisors (150386043621).
65117156699971 is a wasteful number, since it uses less digits than its factorization.
65117156699971 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 150386043620.
The product of its digits is 192893400, while the sum is 73.
The spelling of 65117156699971 in words is "sixty-five trillion, one hundred seventeen billion, one hundred fifty-six million, six hundred ninety-nine thousand, nine hundred seventy-one".
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