Base | Representation |
---|---|
bin | 111100101010101001… |
… | …011010010010010011 |
3 | 20020010201102021021222 |
4 | 330222221122102103 |
5 | 2031401320224313 |
6 | 45531440235255 |
7 | 4464141635003 |
oct | 745251322223 |
9 | 206121367258 |
10 | 65140008083 |
11 | 25697922227 |
12 | 1075b30bb2b |
13 | 61b15c99a7 |
14 | 321d39c003 |
15 | 1a63b13208 |
hex | f2aa5a493 |
65140008083 has 4 divisors (see below), whose sum is σ = 66900548880. Its totient is φ = 63379467288.
The previous prime is 65140008061. The next prime is 65140008091. The reversal of 65140008083 is 38080004156.
65140008083 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 65140008083 - 26 = 65140008019 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (65140068083) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 880270343 + ... + 880270416.
It is an arithmetic number, because the mean of its divisors is an integer number (16725137220).
Almost surely, 265140008083 is an apocalyptic number.
65140008083 is a deficient number, since it is larger than the sum of its proper divisors (1760540797).
65140008083 is a wasteful number, since it uses less digits than its factorization.
65140008083 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1760540796.
The product of its (nonzero) digits is 23040, while the sum is 35.
The spelling of 65140008083 in words is "sixty-five billion, one hundred forty million, eight thousand, eighty-three".
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