Base | Representation |
---|---|
bin | 11101101011010100111110… |
… | …00001110000100110110001 |
3 | 22120001211111120011212000220 |
4 | 32311222133001300212301 |
5 | 32023211300142242001 |
6 | 350444114151003253 |
7 | 16513623402006303 |
oct | 1665523701604661 |
9 | 276054446155026 |
10 | 65260401134001 |
11 | 19880865117827 |
12 | 739baa0369529 |
13 | 2a5504c8395a8 |
14 | 1218898031973 |
15 | 78288d2d5c36 |
hex | 3b5a9f0709b1 |
65260401134001 has 16 divisors (see below), whose sum is σ = 88442311442880. Its totient is φ = 42792744496320.
The previous prime is 65260401133969. The next prime is 65260401134003. The reversal of 65260401134001 is 10043110406256.
It is not a de Polignac number, because 65260401134001 - 25 = 65260401133969 is a prime.
It is not an unprimeable number, because it can be changed into a prime (65260401134003) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4210990 + ... + 12175928.
It is an arithmetic number, because the mean of its divisors is an integer number (5527644465180).
Almost surely, 265260401134001 is an apocalyptic number.
65260401134001 is a gapful number since it is divisible by the number (61) formed by its first and last digit.
It is an amenable number.
65260401134001 is a deficient number, since it is larger than the sum of its proper divisors (23181910308879).
65260401134001 is a wasteful number, since it uses less digits than its factorization.
65260401134001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8009776.
The product of its (nonzero) digits is 17280, while the sum is 33.
The spelling of 65260401134001 in words is "sixty-five trillion, two hundred sixty billion, four hundred one million, one hundred thirty-four thousand, one".
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