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6542640126131 = 58793311128207
BaseRepresentation
bin101111100110101001110…
…1111011001100010110011
3212011110200211200002211112
41133031103233121202303
51324143311333014011
621525351500103535
71243455502324214
oct137152357314263
925143624602745
106542640126131
1120a279986a80a
12898010b34bab
13385c78512125
141889460a940b
15b52c825c58b
hex5f353bd98b3

6542640126131 has 4 divisors (see below), whose sum is σ = 6542651842272. Its totient is φ = 6542628409992.

The previous prime is 6542640126109. The next prime is 6542640126151. The reversal of 6542640126131 is 1316210462456.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 6542640126131 - 26 = 6542640126067 is a prime.

It is a super-2 number, since 2×65426401261312 (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (6542640126151) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4976171 + ... + 6152036.

It is an arithmetic number, because the mean of its divisors is an integer number (1635662960568).

Almost surely, 26542640126131 is an apocalyptic number.

6542640126131 is a deficient number, since it is larger than the sum of its proper divisors (11716141).

6542640126131 is a wasteful number, since it uses less digits than its factorization.

6542640126131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 11716140.

The product of its (nonzero) digits is 207360, while the sum is 41.

Adding to 6542640126131 its reverse (1316210462456), we get a palindrome (7858850588587).

The spelling of 6542640126131 in words is "six trillion, five hundred forty-two billion, six hundred forty million, one hundred twenty-six thousand, one hundred thirty-one".

Divisors: 1 587933 11128207 6542640126131