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65465235113 = 127931511723
BaseRepresentation
bin111100111110000010…
…000011011010101001
320020222101101111220112
4330332002003122221
52033033100010423
650024015104105
74505201213525
oct747602033251
9206871344815
1065465235113
11258444670a3
1210830212035
136233abb115
14325065ad85
151a82456a78
hexf3e0836a9

65465235113 has 4 divisors (see below), whose sum is σ = 65465874768. Its totient is φ = 65464595460.

The previous prime is 65465235097. The next prime is 65465235131. The reversal of 65465235113 is 31153256456.

65465235113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 65465235113 - 24 = 65465235097 is a prime.

It is not an unprimeable number, because it can be changed into a prime (65465225113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 127931 + ... + 383792.

It is an arithmetic number, because the mean of its divisors is an integer number (16366468692).

Almost surely, 265465235113 is an apocalyptic number.

It is an amenable number.

65465235113 is a deficient number, since it is larger than the sum of its proper divisors (639655).

65465235113 is a wasteful number, since it uses less digits than its factorization.

65465235113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 639654.

The product of its digits is 324000, while the sum is 41.

The spelling of 65465235113 in words is "sixty-five billion, four hundred sixty-five million, two hundred thirty-five thousand, one hundred thirteen".

Divisors: 1 127931 511723 65465235113