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65837114113 = 143894575517
BaseRepresentation
bin111101010100001100…
…101010001100000001
320021221022010220222211
4331110030222030001
52034313300122423
650124541502121
74520335144051
oct752414521401
9207838126884
1065837114113
1125a15375311
1210914871941
136292b64a74
143287bc1561
151aa4e1310d
hexf5432a301

65837114113 has 4 divisors (see below), whose sum is σ = 65841704020. Its totient is φ = 65832524208.

The previous prime is 65837114093. The next prime is 65837114137. The reversal of 65837114113 is 31141173856.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 50078831089 + 15758283024 = 223783^2 + 125532^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-65837114113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (65837114143) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2273370 + ... + 2302147.

It is an arithmetic number, because the mean of its divisors is an integer number (16460426005).

Almost surely, 265837114113 is an apocalyptic number.

It is an amenable number.

65837114113 is a deficient number, since it is larger than the sum of its proper divisors (4589907).

65837114113 is a wasteful number, since it uses less digits than its factorization.

65837114113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4589906.

The product of its digits is 60480, while the sum is 40.

Adding to 65837114113 its reverse (31141173856), we get a palindrome (96978287969).

The spelling of 65837114113 in words is "sixty-five billion, eight hundred thirty-seven million, one hundred fourteen thousand, one hundred thirteen".

Divisors: 1 14389 4575517 65837114113