Base | Representation |
---|---|
bin | 111101010101010011… |
… | …101110100001110001 |
3 | 20021222121012102112211 |
4 | 331111103232201301 |
5 | 2034333032302423 |
6 | 50130445052121 |
7 | 4520652405655 |
oct | 752523564161 |
9 | 207877172484 |
10 | 65855744113 |
11 | 25a2493a305 |
12 | 1091ab57041 |
13 | 6296988733 |
14 | 328a470a65 |
15 | 1aa689310d |
hex | f554ee871 |
65855744113 has 4 divisors (see below), whose sum is σ = 66757877668. Its totient is φ = 64953610560.
The previous prime is 65855744069. The next prime is 65855744137. The reversal of 65855744113 is 31144755856.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 26275437409 + 39580306704 = 162097^2 + 198948^2 .
It is a cyclic number.
It is not a de Polignac number, because 65855744113 - 217 = 65855613041 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (65855744173) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 451066668 + ... + 451066813.
It is an arithmetic number, because the mean of its divisors is an integer number (16689469417).
Almost surely, 265855744113 is an apocalyptic number.
It is an amenable number.
65855744113 is a deficient number, since it is larger than the sum of its proper divisors (902133555).
65855744113 is an equidigital number, since it uses as much as digits as its factorization.
65855744113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 902133554.
The product of its digits is 2016000, while the sum is 49.
The spelling of 65855744113 in words is "sixty-five billion, eight hundred fifty-five million, seven hundred forty-four thousand, one hundred thirteen".
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